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7v^2+56v+105=0
a = 7; b = 56; c = +105;
Δ = b2-4ac
Δ = 562-4·7·105
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-14}{2*7}=\frac{-70}{14} =-5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+14}{2*7}=\frac{-42}{14} =-3 $
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